Answer:-[9\-8 + k] + 5 + 6k - 3k²Step-by-step explanation:Since the divisor is in the firm of -c + x, where -c gives you the OPPOSITE terms of what they really, we can use Synthetic Division. The way to do this is to put our c in the top left corner, list all the coefficients in our dividend, then perform our operations:8| -3| 30 | -43 | -49-- ↓ -24 48 40 >> -[9\-8 + k] + 5 + 6k - 3k² ____________________ -3 6 5 -9 ↑ RemainderWhen we perform our operations using synthetic division, we always bring down the first term, then we multiply that term by c, then depending on the outcome, the integer will term us whether or next operation is to subtract or add. We then repeat this process all the up until we reach the end. If we have a remainder, we set it over the divisor given to us in the problem. After this, our quotient will always be one degree less than what was in the dividend. In the problem, our highest degree term was 3, so our quotient will have a highest degree term if 2, then you keep going down the chart over the next coefficients:-3k² + 6x + 5 - [9\k - 8]I am joyous to assist you anytime.