Which expressions show the volume and the surface area of this cubed-shaped packing box?

Answer:[tex]V=(\frac{13}{8})^{3}\ ft^{3}[/tex], [tex]SA=6(\frac{13}{8})^{2}\ ft^{2}[/tex]Step-by-step explanation:we know thatThe volume of a cube is equal to[tex]V=b^{3}[/tex]The surface area of a cube is equal to[tex]SA=6b^{2}[/tex]where b is the length side of the cubeIn this problem we have[tex]b=1\frac{5}{8}\ ft[/tex]Convert to an improper fraction[tex]b=1\frac{5}{8}=\frac{1*8+5}{8}=\frac{13}{8}\ ft[/tex]Part 1) Find the volumesubstitute the value of b in the formula[tex]V=(\frac{13}{8})^{3}\ ft^{3}[/tex]Part 2) Find the Surface areasubstitute the value of b in the formula[tex]SA=6(\frac{13}{8})^{2}\ ft^{2}[/tex]